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Gouri shankar Asked a Question
January 30, 2021 5:37 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

The amount of cu drposited is

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  • Gouri shankar
    nhi answer 1.270 hona chahiye
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  • Dinesh khalmaniya Best Answer
    Equivalent weight of [Cu(CH3CN)4]+ =227/1 =227 mass deposited on cathode = E. W. (I×t) /96500 =227×0.965×2000/96500=4.45 gm in moles = 4.45/227= 0.01960=0.02 mole
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