Gouri Shankar posted an Question
January 30, 2021 • 23:07 pm 30 points
  • IIT JAM
  • Chemistry (CY)

The amount of cu drposited is

1 Answer(s) Answer Now
  • 0 Likes
  • 2 Comments
  • 0 Shares
  • comment-profile-img>
    Dinesh khalmaniya 1 Best Answer

    Equivalent weight of [Cu(CH3CN)4]+ =227/1 =227 mass deposited on cathode = E. W. (I×t) /96500 =227×0.965×2000/96500=4.45 gm in moles = 4.45/227= 0.01960=0.02 mole

whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers