Payal posted an Question
July 19, 2020 • 16:58 pm 30 points
  • IIT JAM
  • Chemistry (CY)

The correct order of basicity is represented by a) pyridine > pyrrole> aniline b) pyrrole > aniline> pyridine c) aniline > pyrrole > pyridine d) pyridine > anil

The correct order of basicity is represented by A) Pyridine > Pyrrole> Aniline B) Pyrrole > Aniline> Pyridine C) Aniline > Pyrrole > Pyridine D) Pyridine > Aniline > Pyrrole -12

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  • Suman Kumar

    Option D is correct

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    Pyridine has localised lone pair. But aniline & pyrrole has delocalized lone pair.

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    But pyrrole lone is compulsory for delocalization to aromaticity. So it is least basic.

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    Priyanshu kumar best-answer

    pyridine is more basic than aniline which is more basic than pyrolle...Option D is correct

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    In case of aniline, the lone pair of electrons on nitrogen atom takes part in the resonance with the pi electron of benzene ring. ... Hence ,the lone pair of electron on 'N'-atom is available for donation to the electron deficient element, ion or group. Consequently, pyridine is more basic than aniline.

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    The lone electrons of N in pyrrole is delocalized . ... Through the lone pair of e− of −NH2 group of aniline is delocalized over the benzene ring, it is not involved in aromatizetion . This pair of lone electron still available for a proton, hence aniline is stronger base than pyrrole.

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    got it meghna??

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    please accept the answer if you got it🙏😊

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    yes sir I got it

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    Thank you

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    Dinesh khalmaniya 1

    Though the lone pair of electrons of -NH2 group of aniline is delocalized over the benzene ring, it is not involved in aromatization. This lone pair is still available for a proton, hence aniline is stronger base than pyrrole.

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