Swastika posted an Question
February 04, 2022 • 20:53 pm 30 points
  • IIT JAM
  • Biotechnology (BT)

The decomposition of a hydrocarbon follows the equation k=(4.5*10" s*) e28000/t the energy of activation for this reaction (in kcal/mol) is ,

The decomposition of a hydrocarbon follows the equation k=(4.5*10" s*) e28000/T The energy of activation for this reaction (in kcal/mol) is ,

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  • Mohanchaitanya reddy Best Answer

    Hello, The answer is -55.638 KCal/mol. Please find attached the PDF for detailed explanation. If you have any question regarding the explanation that I have provided, please reply back. I would be happy to help you. Thank you. Note: In the Explanation, Ea = Energy of Activation R. = Universal Gas constant T. = Absolute Temperature k. = Rate Constant

    4 Feb2022.pdf
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