profile-img
Syed shoaib Asked a Question
January 23, 2022 7:40 pmpts 30 pts
The expectation value of position and momentum of a particle having normalized wave function vr) = N exp (a) (r=0 (P.)0 (6) ()=0 P.)=hk (c) hk P.)=0 d)( hk P.)hk
  • 1 Answer(s)
  • 0 Likes
  • 1 Comments
  • Shares
  • Himanshu thankyou
    answer is b because expection value of momentum of real wave function is zero always .but here wave is not real then expectation value of momentum has some answer and expectation v...
    Show more
    Likes(0) Reply(0)