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Arindam Paul posted an Question
January 17, 2021 • 21:11 pm 30 points
  • IIT JAM
  • Biotechnology (BT)

The molar enthalpy of vaporization for a liquid (normal boiling point = 78.3 °c) is 39 kj mol". if the liquid has to boil at 25 °cythe pressure must be reduced

The molar enthalpy of vaporization for a liquid (normal boiling point = 78.3 °C) is 39 kJ mol". If the liquid has to boil at 25 °Cythe pressure must be reduced to_ place). (Given: R =8.314 JKmol;1 atm = 760 Torr) Torr (up to one decimal

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    Krishan k jakhad

    Boiling Point of a given substance is the temperature at which the vapor pressure of a liquid substance is equal to the surrounding atmospheric pressure. you are provided with an example similarly you hv to solve this problem. using Clausius Clapeyron equation

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