IIT JAM
Meghna Asked a Question
July 12, 2020 1:23 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

The number of component for kci-nacl-h,o and kc-nabr-h,0 systems are, a) 1 and2 c) 3 and 4 65 b) 3 and3 d) 4 and 5 d iviaiand to ha 20 2v40 sm2mal

The number of component for KCI-NaCl-H,O and KC-NaBr-H,0 systems are, A) 1 and2 C) 3 and 4 65 B) 3 and3 D) 4 and 5 d iviaiand to ha 20 2v40 Sm2mal
  • 2 Answer(s)
Answer Now
  • 0 Likes
  • 6 Comments
  • Shares
  • Priyanshu kumar Best Answer
    see this
    • cropped2450913518976193728.jpg
    Likes(1) Reply(1)
    Priyanshu kumar
    meghna any doubt then please ask??
  • Suman Kumar thankyou
    See this
    • cropped3457019051371130865.jpg
    Likes(1) Reply(4)
    Suman Kumar
    Option C is right Meghna
  • Priyanshu kumar
    see
    • cropped928011606287445622.jpg
    Likes(1) Reply(4)
    Meghna
    sir,in this solution I can't understand the last line i.e 'Three components reduced to two independent components
  • Priyanshu kumar
    ans is option C
    Likes(0) Reply(1)
    Priyanshu kumar
    see explanation
    • cropped2554525499087494377.jpg
  • Priyanshu kumar
    hope this will help ušŸ˜ŠšŸ™
    Likes(0) Reply(0)
  • Suman Kumar
    Hope you have got this
    Likes(0) Reply(0)
How Eduncle Helps You ?
StudentTutorInstitutionApp
Help
FAQsPayment TermsRefund PolicyAsk Support
Head Office :
MPA 44, 2nd floor, Rangbari main Road Mahaveer Nagar II, Kota (Raj.) - 324005

Branch Office (Jaipur):
Shyam Tower, Plot No. F2, 6th Floor Amrapali Circle,
Vaishali Nagar, Jaipur, Rajasthan 302021

Mail: info@eduncle.com
All Rights Reserved Ā© Eduncle.com