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The number of unpaired electron (s) present in the species [fe(h,o)-(no)] which is formed during brown ring test is (a) 2 for [fef1and [felcn) 13 (b)3 3 (c) 4 (
The number of unpaired electron (s) present in the species [Fe(H,O)-(NO)] which is formed during brown ring test is (a) 2 For [FeF1and [FelCN) 13 (b)3 3 (c) 4 (d) 5 mas
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Priyanshu kumar
Hope this will helps u😊🙏
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Priyanshu kumar Best Answer
check this reshav
![cropped523803128339431988.jpg]()
![eduncle-logo-app]()
Check this
![eduncle-logo-app]()
Any doubt reshav??
![eduncle-logo-app]()
one pairing means?
![eduncle-logo-app]()
fe+ configuration 3d6 4s1
![eduncle-logo-app]()
so 1 electron from 4s pairs with 3d
![eduncle-logo-app]()
and 3 unpaired electrons left
![eduncle-logo-app]()
now clear reshav??
![eduncle-logo-app]()
dear reshav check the previous query too
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Reshav
explain sir
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Priyanshu kumar
3 unpaired electrons...Option B is correct answer
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Suman Kumar![best-answer]()
In Brown ring iron is in +1 Oxidation State
The oxidation state of Fe in the brown ring complex is +1 and the electronic configuration thus becomes 3d64s1. Then the weak field ligand water and strong field ligand attack the metal ion and change the configuration to 3d74s0 and therefore the complex is left with 3 unpaired electrons.
The oxidation state of Fe in the given complex is +1. Therefore, its configuration becomes 3d64s1. When the weak feild ligand like water and strong field ligand like NO attacks the configuration changes to 3d74s0. Hence , the number of unpaired electrons in the 3d subshell is 3. Therefore option B is correct.
https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.toppr.com/ask/question/how-many-unpaired-electrons-are-present-in-the-brown-ring-complex-feh2o5noso4/&ved=2ahUKEwiSrrWu2LHrAhV1xzgGHfOZBTIQFjALegQICBAB&usg=AOvVaw3kFkozG379mK9zlLtIGH01&cshid=1598198341755
Hence option B is correct