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Vaishnavi Mishra posted an Question
September 20, 2021 • 12:06 pm 10 points
  • IIT JAM
  • Mathematics (MA)

The open interval (a, b) is a nbd. of all its points, since x e (a + 6, b - e)c (a,b) 2 the half open interval (a, b] is a nbd, of all its points except b, sinc

The open interval (a, b) is a nbd. of all its points, since X E (a + 6, b - e)c (a,b) 2 The half open interval (a, b] is a nbd, of all its points except b, since for anye>0 ( b+e > b) 3. be [b 8, b + e) (a, b]. Similarly, [a, b) is a nbd. of all its points except a and [a, b] is a nbd. of all its points except a and b. f au af ito nainte since for anv integer p and any explain neighborhood end point of open and close interval

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  • Anonymous User best-answer

    nbd of a (a-$,a+$) not containd in [a,b) so [a,b) is not open similarly nbd of a,b not containd in[a,b] so it is not open

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