Swastika Asked a Question
June 7, 2021 8:22 pmpts 30 pts
The pH of gastric juice in the stomach is 2.0, However the pH inside the cells that Iine the stomach is 7.0. For transport of protons from inside the cell to the stomach, the free energy change (AG) in kJmol- at 37°C is Assume Universal Gas constant R = 8.314 Jmol-K-]
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  • Abhijeet Gaurav Best Answer
    Correct Answer is = 29.6 KJmol-1
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