Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Priyanshu kumar
option C is correct
C is most stable as after solvolysis aromatic compound is formed cyclopropenyl cation
In 4th one antiaromatic compound is formed after solvolysis so least stable
In 1st one after solvolysis carbocation is formed which according to bredts rule is unstable...i.e bridge head carbon can't be sp2 hybridised
please ask me rutik if any doubt