Rutik posted an Question
February 11, 2021 • 17:08 pm 30 points
  • IIT JAM
  • Chemistry (CY)

The rate of solvolysis of -iv follows br br (iv) (m0) a (b) il >i> l > iv (a) (c) (d) iv>>l ll l>11>i> iv

The rate of solvolysis of -IV follows Br Br (IV) (M0) A (B) Il >I> l > IV (A) (C) (D) IV>>l ll l>11>I> IV

2 Answer(s) Answer Now
  • 0 Likes
  • 2 Comments
  • 0 Shares
  • comment-profile-img>
    Priyanshu kumar best-answer

    option C is correct

    eduncle-logo-app

    C is most stable as after solvolysis aromatic compound is formed cyclopropenyl cation

    eduncle-logo-app

    In 4th one antiaromatic compound is formed after solvolysis so least stable

    eduncle-logo-app

    In 1st one after solvolysis carbocation is formed which according to bredts rule is unstable...i.e bridge head carbon can't be sp2 hybridised

    eduncle-logo-app

    please ask me rutik if any doubt

  • comment-profile-img>
    Dinesh khalmaniya 1 best-answer

    option C Explanation- After solvolysis carbocation is formed. C formed most stable aromatic carbocation while D formed least stable Antiaromatic carbocation. in case of A and B, A formed less stable carbocation than B because in A, bridge head carbocation is formed which is unstable because of non planarity of bridge head position. while B has allylic carbocation

whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers