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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Priya sarda
Here is the solution of your query - Log10 (MW) = -2Rf+ 3 Log10 (MW) = -2*.5 + 3 Log10 (MW) = -1 + 3 MW = 100 kDa MW of 180 amino acids is = 180*110 Da = 19.8 kDa ~ 20kDa So, the number of identical monomers in the protein is = 100/20= 5 Thank you