IIT JAM
   Top Resources
Shifana posted an Question
December 14, 2020 • 21:18 pm 30 points
  • IIT JAM
  • Chemistry (CY)

The rusting of iron takes place as follows: 2h +2e+0, > h,o(); e° =+ 1.23 v fe2+2e fe (s); e = -0.44v the ag° for the net process is: (a) -322 kj mol-1 (b) -161

The rusting of iron takes place as follows: 2H +2e+0, > H,O(); E° =+ 1.23 V Fe2+2e Fe (s); E = -0.44V The AG° for the net process is: (A) -322 kJ mol-1 (B) -161 kJ mol-1 (C) -152 kJ mol-1 (D) -76 kJ mol

1 Answer(s) Answer Now
  • 0 Likes
  • 3 Comments
  • 0 Shares
  • comment-profile-img>
    Priyanshu kumar

    Option A is correct https://doubtnut.com/question-answer-chemistry/the-rusting-of-iron-takes-place-as-follows-2ho-2e-1-2-o2-rarr-h2olec-123v-fe2-2e-rarr-fesec-044v-del-11044241 check this video solution too

    cropped2573448013918336723.jpg
  • comment-profile-img>
    Dinesh khalmaniya 1

    option A video solution - https://www.google.com/amp/s/amp.doubtnut.com/question-answer-chemistry/the-rusting-of-iron-takes-place-as-follows-2ho-2e-1-2-o2-rarr-h2olec-123v-fe2-2e-rarr-fesec-044v-del-11044241

    cropped2290366782049400583.jpg
whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers

Sign Up to Download FREE Study Material Worth Rs. 500/-