Yash Singh posted an Question
August 11, 2020 • 02:14 am 30 points
  • IIT JAM
  • Mathematics (MA)

The solution of the given initial value problem y+3y'=0, y(0)=-2, y(0)=3 is (a) y=12-8 (b) y=e"+2 (c)y-+2 (d) y=--1

The solution of the given initial value problem y+3y'=0, y(0)=-2, y(0)=3 is (A) y=12-8 (B) y=e"+2 (C)y-+2 (D) y=--1

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