Vijay posted an Question
May 30, 2020 • 19:12 pm 30 points
  • IIT JAM
  • Physics (PH)

The tds- equations

I'm unable to get the second step ie...how it came. This is screenshot of book Thermal Physics by SC Garg, CK Ghosh. Please explain it....

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    Ruby negi best-answer

    you can go through the solution of vaishali. and for any doubt you can ask.you have to know these types of partial derivative in thermodynamics. and also remember all Maxwell's equations.

  • comment-profile-img>
    Ruby negi

    dear, look S is the function of T,V so when you do partial derivative of S then you get dT and dV so TdS/dT at constant V is Cv and dS/dV=dP/dT (according to Maxwell equation)....

    eduncle-logo-app

    Nice approach!

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    Dhairya sharma best-answer

    I used the concept of Maxwell equation and partial derivation see your solution I hv al attached.

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