Shirin posted an Question
January 27, 2022 • 13:53 pm 30 points
  • IIT JAM
  • Biotechnology (BT)

The total number of genetically different types of gametes that will be produced by a heterozygous plant carrying the genotypes aabbc¢ is

The total number of genetically different types of gametes that will be produced by a heterozygous plant carrying the genotypes AABbC¢ is

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  • Mohanchaitanya reddy best-answer

    Hello, Correct answer is 4. Here, AABbCc plant is, 1)Homozygously dominant for AA, 2) Heterozygous for Bb and Cc. So, According to the Law of segregation, Total 4 genetically different gametes will be formed and they are: ABC, ABc, AbC, Abc. Note: As a short trick you can use, Number of genetically different types gametes for an individual = 2^n, Where n = No.of Heterozygous sets genes are present. Here, Bb and Cc are the Two Heterozygous pairs of genes present so, 2^2 = 4. Please reply back if have any sort of questions regarding to the solution I have provided. Thank you.

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