Ashwini Asked a Question
April 16, 2020 3:01 pmpts 30 pts
  • 1 Answer(s)
  • 0 Likes
  • 6 Comments
  • Shares
  • Arzoo
    Ashwini I suggest you to take this question on hold. Because there is a loophole on the points lie on the line y=-x by both way hit and trial and piecewise defined fn as above.
    Likes(0) Reply(0)
  • Arzoo
    Sir, I think piecewise defined fn in last step is not even continuous on points that lies on line y=-x.
    Likes(0) Reply(0)
  • Lov kumar
    K=0
    • cropped3133352884197499419.jpg
    • cropped7550651242928756151.jpg
    Likes(0) Reply(0)
  • Arzoo
    I am just telling you that this hit and trial method sometimes work in exam too in NAT section. But at this time you have time so do this question with right method.
    Likes(0) Reply(0)
  • Arzoo thankyou
    If we do not talk about method and just simply observe, Then we will get that if we take k=0 then given function becomes constant function that is 1, which is differentiable everyw...
    Show more
    Likes(0) Reply(0)
  • Arzoo
    we can take value k=0, it will satisfy given statement.
    Likes(0) Reply(1)
    Ashwini
    plz give explanation