Neha Hema raj Asked a Question
October 2, 2020 1:37 pmpts 30 pts
The value of lex 1+n x"-1-x2n =dx is (1-x" )1-x2n ev1-x+C (A) +C (B) ex V1+x2n C +C 1-x2n 1-x ev1-xan +C 1+x 1-x (C) (D) e +C 1-x
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  • Vishal goswami Best Answer
    see attachment
    • cropped3561081078193066092.jpg
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