Mounika sarswat Asked a Question
May 16, 2021 10:46 pmpts 20 pts
There are two boxes, each containing two components. Each component is defective with probability 1/4, independent of all other components. The probability that exactly one box contains exactly one defective component equals (B) 5/8 (A) 3/8 (C) 15/32 (D) 17/32 Show the steps ..
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  • Anuj s. thankyou
    ans is 3/8 by total probability theorem P(selecting box) = 1/2 P(defective)=1/4 P(non defective) = 1-1/4 = 3/4 P = 1/2*1/4*3/4 + 1/2*3/4*3/4 = 12/32 = 3/8
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