Surabhi Asked a Question
May 14, 2020 3:10 pmpts 30 pts
Therefore the given vectols Example: The following vectors of V,(R) are LD: a, = (1, 3, 2); a, = (1, -7,-3); a, = (2, 1, -1) Solution. Let a,, a, a, e R be real numbers such that a,a, +a, + a,a, 0 a,(1, 3, 2) +a,(1, -7, -8) + a,(2, 1, -1) = (0, 0, 0) (a, + a, + 2a,. 3a,- (a, * a 2a, - 8a,a) = (0, 0, 0) a, + a,+ 2a,u 2a, + a, 4a, = 0 a, +5a, + 7a, = 0 (1) 2 3 4) From (1) and (3), From (1) and (4), Therefore a, = 3, a, -2, a, a,-2a, a, 3a, 1IS a non zero solution of the above equations onsequent 3a,- 2a,+a, =0 a a, are LD. why the equations are different from the given question?
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  • Rishita Best Answer
    we get all three constants alpha beta gamma as zero therefore no vector can be written as combination of other two
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    Rishita
    add vectors component wise x coordinate with x similarly with others
  • Arzoo thankyou
    See
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    Arzoo
    Accept the answer if you get your doubt clear
  • Ujjawal vishal
    mistake in calculation... you are thinking right...
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