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Surabhi Asked a Question
May 14, 2020 3:10 pm 30 pts
Therefore the given vectols Example: The following vectors of V,(R) are LD: a, = (1, 3, 2); a, = (1, -7,-3); a, = (2, 1, -1) Solution. Let a,, a, a, e R be real numbers such that a,a, +a, + a,a, 0 a,(1, 3, 2) +a,(1, -7, -8) + a,(2, 1, -1) = (0, 0, 0) (a, + a, + 2a,. 3a,- (a, * a 2a, - 8a,a) = (0, 0, 0) a, + a,+ 2a,u 2a, + a, 4a, = 0 a, +5a, + 7a, = 0 (1) 2 3 4) From (1) and (3), From (1) and (4), Therefore a, = 3, a, -2, a, a,-2a, a, 3a, 1IS a non zero solution of the above equations onsequent 3a,- 2a,+a, =0 a a, are LD. why the equations are different from the given question?
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• Anonymous User Best Answer
we get all three constants alpha beta gamma as zero therefore no vector can be written as combination of other two
Anonymous User
add vectors component wise x coordinate with x similarly with others
• Arzoo
See
Arzoo
Accept the answer if you get your doubt clear
• Ujjawal vishal
mistake in calculation... you are thinking right...