In case of constant pressure, dQ=nCpdT and dW=dQ-dU where dU=nCvdT so for calculating dW/dQ=1-Cv/Cp =1-(1/gamma) and you know gamma=7/5 in case of diatomic so u will get 1-(5/7)=2/...
Option D is correct. You can directly use this formula(which I have encircled, i.e. equation 2, in my solution) if fractiom of heat converted to work at constant pressure is asked...
answer:here is the solution attached, ans is option d .I have used here f=5 for diatomic at room temperature ,this thing have to remembered for exam purpose ,bcz without this it is...
30 pts
