Himanshu posted an Question
April 21, 2020 • 01:34 am 30 points
  • IIT JAM
  • Physics (PH)

Thermodynamic

Answer of this question is 15Kw .

3 Answer(s) Answer Now
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  • comment-profile-img>
    Ruby negi best-answer

    area under the curve is work done, u know power = work done/time. PV curve is rectangle so area of curve is 4PoVo. using power formula u will get ur ans and that is 15KW. best regards

  • comment-profile-img>
    Abhishek singh Best Answer

    I would like to share a trick to handle this type of questions. I am assuming, you must be knowing (atleast by now) about how to calculate workdone per cycle by given PV diagram. But sometimes students get confused in exam like how this work per cycle and a given revolution rate combinely will give the power. Then just go dimensionally. Many questions in exam will help you if you know(or remember) dimensional approach. dimensionally work done multiplied by a revolution rate will give dimensions of power. do remember this. Best regards.

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    Abhishek singh best-answer

    I would like to give a suggestion about this type of questions. if you got confused in exam (like how to calculate power, I can calculate work done, but some revolution rate is give, what to do with rate and all.) Then use this method, this will let you score atleast 5% more in any exam. The method is to go dimensionally. if you multiply work by some rate, you will get dimensions of power. Remember this approach. Best regards.

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  • comment-profile-img>
    Shanu arora

    here is the solution , area in pv diagram gives the work done by the engine. To calculate the power one need to accommodate revolution per sec as well which is 1500/60 here. feel free to ask any doubts .

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