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Roni pramanik Asked a Question
February 20, 2021 1:17 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Thermodynamics please answer my questions as soon as possible

thermodynamics please answer my questions as soon as possible
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  • Dinesh khalmaniya Best Answer
    option A Use this formula ∆H = ∆E + ∆ngRT 40.52 = ∆E + 1 × 8.314× 373/1000 ∆E = 40.52 - 3.1= 37.41kj/mol
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    Roni pramanik
    how calculated deale ngRT value?
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