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Sahiba Naqvi posted an Question

July 20, 2020 • 06:28 am

30 points

IIT JAM
Chemistry (CY)

These compounds are optically active or inactive and how?

3 Answer(s)

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Suman Kumar

Sahiba both are optically active.
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Please ask if you don't get anything Sahiba
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https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.slideshare.net/mobile/zarojabeen50/diphenyl&ved=2ahUKEwix8oeh9drqAhUOOSsKHQg8D8cQFjAOegQIBhAB&usg=AOvVaw0ad_7O1R1VEtDWSPoy_7eF&cshid=1595217081723
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You can see this.
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All the condition are mentioned for optical activity
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Read this. please ask if you don't get anything
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Hope you like it 🙏
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Sahiba naqvi

sir but in (2) it depends on G .
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yes it depends on G. 2nd will become optically inactive only if G=H
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Sahiba naqvi

So , both these are optically inactive?
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No Sahiba
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Ist one is definitely optically active
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2nd one depends on G
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Priyanshu kumar Best Answer

see as in both the compounds ortho position is not substituted by bulky group..so there is no restricted rotation,no properly substitution..This condradicts the conditions of biphenyl to show optical activity..So the compounds are optically inactive
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got it or any doubt then please ask😊
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Sahiba naqvi

if we draw the bisecting plane (slice cut) than it will become optically inactive
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you can do slice cut but only one benzene will be bisected other will get into two halves.
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See this
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Now you do slice cut with substitution of H.
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Boddu rama krishna

both optically active
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Sahiba naqvi

whenever bulky group present it become optically active.
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yes, but these bulky groups must be present at all Ortho position of both the rings
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Dinesh khalmaniya 1

check it
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ortho position must be occupied by bulky groups make it optically active
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example
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got it??
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in your question, all the orth position in both the rings doesn't occupied bulky groups. here H also present at Ortho position.
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now got it??
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Dinesh khalmaniya 1

no, optically active
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