Surya Asked a Question
April 30, 2022 2:26 pmpts 30 pts
Two long thin conducting tubes are concentric with each other. The outer tube has a radius R and has a current I while the inner tube has a radius R/4. To cancel the field at points r > R, the inner tube must have a current a.) running parallel to I of magnitude I/4 b.) running parallel to I of magnitude I c.) running antiparallel to I of magnitude 1/4 d.) running antiparallel to I of magnitude I
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  • Sachin thankyou
    B can be zero only when the net current passing through the loop is zero. so antiparallel current
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  • Sachin
    Acc to ampere circutal law intgration of B.dl = mu naught * I. This I is the I surrounded by the path chosen for the line integral of B. To cancel B field the current should be of ...
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