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Vijay posted an Question
September 21, 2021 • 20:28 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Usp4nat13. please send the solution to the problem given in the attachment.

usp4nat13. please send the solution to the problem given in the attachment.

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  • Anonymous User Best Answer

    m>2 so minimum value of m is 3

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    doubt

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    cos(1/h) and sin(1/h) lie between -1 to 1 so limit is zero only when h^(m-1) and h^(m-2) equal to zero it is possible when h ki power positive so m>2. m>2 minimum value 3

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    apne h^(m-1) cancel kiya hai wo cancel nahi hoga because h^(m-1) limit mai hai

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    if any dabut tell me

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    apne h^(m-1) cancel kiya hai wo cancel nahi hoga because h^(m-1) limit mai hai par limit same hai isleye cancel kiya mene

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    cos(1/h) and sin(1/h) lie between -1 to 1 so limit is zero only when h^(m-1) and h^(m-2) equal to zero it is possible when h ki power positive so m>2. m>2 minimum value 3. sin and cos 1/h 0 bhi toh ho sakte hai na sir

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    nahi cos(infinite) or sin(infinite) ki value fix nahi iski range -1 to 1 hoti hai vase bhi same angle par sin or cos ek sath zero nahi ho skte

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    understand or not

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