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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Mathematics (MA)
Usp4nat13. please send the solution to the problem given in the attachment.
usp4nat13. please send the solution to the problem given in the attachment.
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Anonymous User Best Answer
m>2 so minimum value of m is 3
doubt
cos(1/h) and sin(1/h) lie between -1 to 1 so limit is zero only when h^(m-1) and h^(m-2) equal to zero it is possible when h ki power positive so m>2. m>2 minimum value 3
apne h^(m-1) cancel kiya hai wo cancel nahi hoga because h^(m-1) limit mai hai
if any dabut tell me
apne h^(m-1) cancel kiya hai wo cancel nahi hoga because h^(m-1) limit mai hai par limit same hai isleye cancel kiya mene
cos(1/h) and sin(1/h) lie between -1 to 1 so limit is zero only when h^(m-1) and h^(m-2) equal to zero it is possible when h ki power positive so m>2. m>2 minimum value 3. sin and cos 1/h 0 bhi toh ho sakte hai na sir
nahi cos(infinite) or sin(infinite) ki value fix nahi iski range -1 to 1 hoti hai vase bhi same angle par sin or cos ek sath zero nahi ho skte
understand or not