30 points
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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Mathematics (MA)
Vmcq11. please send the solution to the problem given in the attachment.
2 Answer(s)
Answer Now
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Anonymous User Best Answer
C check attachment
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Arpan pal
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option (d) is correct. since Xn+1 =(Xn+Yn)/2 and Yn+1=√(Xn.Yn) Then applying A.M≥G.M we have Xn+1=(Xn+Yn)/2 ≥√(Xn.Yn)=Yn+1 for all n≥2 i.e.,Xn≥Yn for all n≥1 Taking limit both sides, we have limXn≥limYn .
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C is correct option acc.to the book
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pls explain the last 3rd step
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Xn+1≥Yn+1.It is true for all n≥2.If you put n+1=n,then Xn≥Yn and this true for all n+1≥2 i.e.,n≥1
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Anonymous User
c is correct answer