IIT JAM
Sadhana Jaiswal Asked a Question
January 3, 2020 3:36 pmpts 15 pts
  • IIT JAM
  • Chemistry (CY)

Void fraction = 1 -0.52 = 0.48, Void space = 48%% Problem 8: The density of solid argon is 1.65 g/mL at -233°C. If the argon atom is assumed to be sphere of rad

Void fraction = 1 -0.52 = 0.48, Void space = 48%% Problem 8: The density of solid argon is 1.65 g/mL at -233°C. If the argon atom is assumed to be sphere of radius 1.54 x 10 cm, what percentage of solid argon is apparently empty space ? (At. wt. of Ar = 40).
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  • Sadhana Jaiswal
    thanks
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  • Eduncle Best Answer

    Dear Sadhna,

    Greetings!

    Refer the attached image for solution

    Thank you for asking your query.

    • Solution.JPG
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