30 points
>
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
What is the relationship between following compounds?
Keialioil DeLweeII Liese LWO COImpouna is 1A4/ CR/Un \K H CH H C H,CH, H CI HOH H OH (a) Enantiomers b) Diastereomers (c) Identical (d) Constitutional isomers uwi,.
3 Answer(s)
Answer Now
- 0 Likes
- 7 Comments
- 0 Shares
-
![comment-profile-img]()
>
Dinesh khalmaniya 1
check the chart to understand how the molecules are related to each other. to find out relationship please find out the configuration of each chiral centre. if same configuration such as R|R,S|S or RR|SS is obtained then identical if R|S,S|R or RR|SS or RS|SR then enantiomers, if RR|RS or SS|SR the diastereoisomers
![cropped1080054792405819561.jpg]()
![eduncle-logo-app]()
got it??
![eduncle-logo-app]()
please accept the answer if you got it 🙏🙏
-
![comment-profile-img]()
>
Priyanshu kumar
reshav for this type of problems...first of all name R and S configuration...and then check one by one....1. if mirror images but superimposable then identical and same R and S configuration. 2. if mirror images but non superimposable and opposite R and S configuaration then enantiomers.... 3.. if non mirror images and one or more diff R and S configuration then diastereomers....
![eduncle-logo-app]()
hope this much helps😊🙏 and please accept the answer if it helps
![eduncle-logo-app]()
reshav any doubt??
-
![comment-profile-img]()
>
Dinesh khalmaniya 1
hope this will help you 🙏🙏🙏
-
![comment-profile-img]()
>
-
![comment-profile-img]()
>
Dinesh khalmaniya 1
Option A, enantiomers
-
![comment-profile-img]()
>
Priyanshu kumar Best Answer
these are enantiomers ...Option A
![cropped3971884836991121226.jpg]()
![eduncle-logo-app]()
got it reshav...please accept the answer if it helps😊🙏
![eduncle-logo-app]()
why you dont do the R S configuration to one centre
![eduncle-logo-app]()
reshav at first carbon see...there is 2 methyl group and properties of chiral carbon is that they must have 4 diff group . 2 groups are same in first carbon that is methyl group
![eduncle-logo-app]()
got it reshav??
![eduncle-logo-app]()
if you got it then please accept the answer 🙏
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Suman Kumar![best-answer]()
Find R/S at all position. You can solve on your own.
Reshav do this first.
Show me your work.
is it correct way to solve?
This is also correct way to do Reshav. Great! keep it up 👍
Say Reshav
with R S configuration is it correct
Yes this method will always give you correct information. You may get confusion while doing conversion into fisher. But this way it will save your time