Shweta Thakur posted an Question
June 04, 2020 • 02:34 am 30 points
  • IIT JAM
  • Chemistry (CY)

What is the role of ch3i in making ammonium cation for hoffman elimination .see first step

sir Hoffman elimination involve tertiary ammonium cation which is same as Hoffman ammonolysis product

3 Answer(s) Answer Now
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  • Suman Kumar Best Answer

    Absolutely you can use this but salt must have atleast 2 carbon so that you can remove H for elimination.

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    Like in this case ethyl is present so you can eliminate H .

  • Shweta thakur

    and sir can I use Hoffman aminolysis product, I am sending plz tell me this ,....because sir ultimately HMe ammonium cation Chahiye Jo is salt main available hai

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  • Suman Kumar best-answer

    CH3I is used for methylation of Nitrogen. This is called exhaustive methylation because nitrogen will get methylated till it form 4 bond. After donation of lone pair it acquires +ve charge which helps in Hoffman elimination (i.e adjacent H is removed)

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    Dinesh khalmaniya 1 best-answer

    CH3I methylates the amine group to form ammonium ion. it is very good leaving group and easily can eliminate

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    ch3i is good leaving group

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    yes in CH3I, iodine is going leaving group and gives SN2 with nucleophile

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    do you still have any doubt??

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    this is sn2 reaction

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    ch3i is strong base

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    yes

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    I have sent u one more thing plz check that also ,relating to this question

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    yes, i checked but I'm unable to understand your question, can you explain again so i can give proper reply

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    sir I am saying that can I use quatarnary salt obtained by (Hoffman ammonolysis) in this reaction for ammonium cation

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    I have sent u the picture

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