Shweta thakur Asked a Question
September 23, 2020 8:06 pmpts 30 pts
Lal 20. The heats of combustion of graphite and diamond at 298 K are -393 and -395 kJ/mole respectively. The specific heats of these substances are 720 and 505 J kg Krespectively. Calculate the heat of transformation of graphite into 28. A heat pu 15°C and from the diamond at 273 K. (2-0645 kJ mole 29. Given the 12 [Hint: AH= [-393 -(395) }+ (0-720-0-505) 1000 x (298-273) ]
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  • Priyanshu kumar Best Answer
    Here at different temperature it is asking for finding of heat of transformation. So it is used here,if it is asking only for same temperature given then you can proceed directly �...
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    Shweta thakur
    see the hint ..also and I am getting 2 answer right n
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