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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Pratiksha Gandhi posted an Question
June 06, 2020 • 21:36 pm
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10 points
10 points
- IIT JAM
- Chemistry (CY)
What will the answer of following question ? and how ?
what will the answer of following question ? and how ?
2 Answer(s)
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Dinesh khalmaniya 1
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Given: density of mixture=0.2g/L ,T=300K,P=1atm Using formula d=PM/RT Hence, M= (d×R×T)/P M=(0.2×0.0821×300)/1 M=4.926g Now, let mole fraction of N2 (X1) be 'n' and mole fraction of H2(X2) be '(1-n)' M1=( 2×14=28)=mol.mass of N2 M2=(2×1=2)=mol.mass of H2 Applying formula of molar mass of mixture— M= M1 X1 +M2 X2 4.926={ 28×n + 2×(1-n) } solving for ‘n’ we find n=0.11 Hence the mole fraction of N2 (g)in the vessel is 0.11
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Dinesh khalmaniya 1 Best Answer
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