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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
Which option is correct?
Which option is correct? ....................................
2 Answer(s)
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Priyanshu kumar Best Answer
option A Due to presence of vacant d orbitals in P, electons present in 3 p can excites to vacant 3 d orbitals, so its valency is 5 so P can form R3P=O. Whereas due to absence of d orbitals in N, it can't be pentavalent hence unable to form R3N=O. So 1st is more favorable than 2nd
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Dinesh khalmaniya 1![best-answer]()
option A Explanation- Phosphorus can easily assume +5 oxidation state in compounds due to the presence of unfilled 3d-orbitals. For example, PCl3 (O.S. +3) and PCl5 (O.S. +5) are stable, and so is POCl3 (O.S. +5). Similarly, R3P (trialkylphosphine) (O.S. +3) is easily oxidized to R3PO (O.S. +5). Nitrogen is not able to access 3d-orbitals easily, and hence does not form stable compounds with +5 oxidation state. R3N (trialkylamine) can be oxidized to form R3NO (trialkylamine oxide), but the structure is generally written as [R3N]+-O-. Similarly, it can also form tetralklylammonium salts (R4N+X-).