Simun Mishra posted an Question
July 08, 2020 • 20:50 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Why in case of ainline 3 products forms o..m ..p are form ?

2 Answer(s) Answer Now
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  • Simun mishra

    why in case of this tri bromo product formed

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    pls check it

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    simun Nh2 group is highly activating towards electrophilic substitution and reaction doesnt stop in mono substitution stage rather it give tri substituted product with bromine water...and if you want to get mono substitution product then you have to reduce the activation nature of NH2 grp by reacting it with acetyl chloride...so that acetanilide is obtained and after that do bromination you get mono substituted product

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    the image you have send above...in this aniline with br2 in non aqueous solvent like CCL4,CS2 gives one major para product and one minor ortho product

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    simun read above written explanation and if you have any doubt in it then ask..

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    ok

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    you told that in aq solvent like ccl4 2 major products are formed but here tri bromo product is formed

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    no it is given wrong here simun

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    pls send me write ine

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    one

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    see simun

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    yaa I can understand now

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    Aniline is strongly activated and the NH2 group is ortho para directing. Since it is strongly activated, tribromination will occur and all the 2 ortho positions and the para position will be brominated. So, the product will be 2,4,6-tribromoaniline.

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    in case of ccl4 also tribromo product form or not

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    yes, in aqueous as well as in both the case it will give same product

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    ok means this reaction is correct

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    yes

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    but in the case of phenol only aqueous bromination give 2,4,6 tribromo product while non aqueous Bromomide gives para product as a major product

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    hope you will get it

  • Suman Kumar

    -NH2 is a strong activating group towards electrophilic substitution in benzene ring hence para & ortho product. Ortho is less due to steric reason . At the same time it is a good Lewis base. So it abstract proton from and become anilinium ion. Now the game changes. Nitrogen with positive charge become eletron withdrawing group so it deactivate the rings hence responsible for meta product.

  • comment-profile-img>
    Priyanshu kumar Best Answer

    simun see this for more clear understanding

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    I m sending an image pls check it

  • comment-profile-img>
    Dinesh khalmaniya 1 best-answer

    check it

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    any doubt?

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    it is only for aniline or for any other compounds

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    it's for aniline because it is basic and accept H to form NH3+ so it become meta directive

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    got it?

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    why in case of phenol also tri nitro phenol is formed

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    actually OH group is strong electron releasing group so it increases electron density at all the ortho and para position

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    so why in meta position their is a nitro group

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    in which cases hyrogenbonding occurs

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    H bonding occurs between High EN atom such as F,O,N and H atom of another group

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    got it

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    please accept the answer if you got it 🙏

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    ok

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    I m sending an image pls check it

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    okay

  • comment-profile-img>
    Priyanshu kumar

    Aniline is base when it react with acids it forms anilinium ion which is meta directing...so all three products are formed

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