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Simun mishra
why in case of this tri bromo product formed
pls check it
simun Nh2 group is highly activating towards electrophilic substitution and reaction doesnt stop in mono substitution stage rather it give tri substituted product with bromine water...and if you want to get mono substitution product then you have to reduce the activation nature of NH2 grp by reacting it with acetyl chloride...so that acetanilide is obtained and after that do bromination you get mono substituted product
the image you have send above...in this aniline with br2 in non aqueous solvent like CCL4,CS2 gives one major para product and one minor ortho product
simun read above written explanation and if you have any doubt in it then ask..
ok
you told that in aq solvent like ccl4 2 major products are formed but here tri bromo product is formed
no it is given wrong here simun
pls send me write ine
one
see simun
yaa I can understand now
Aniline is strongly activated and the NH2 group is ortho para directing. Since it is strongly activated, tribromination will occur and all the 2 ortho positions and the para position will be brominated. So, the product will be 2,4,6-tribromoaniline.
in case of ccl4 also tribromo product form or not
yes, in aqueous as well as in both the case it will give same product
ok means this reaction is correct
yes
but in the case of phenol only aqueous bromination give 2,4,6 tribromo product while non aqueous Bromomide gives para product as a major product
hope you will get it