Why in presence of k2s2o8 in phenol the hydroxylation occqure in only para position ?

check the mechanism. here phenoxide ion tautomerised to give a stable intermediate Carbanion. str 2

sir their is some proble I can't get any reply from ur side

now got it?

I m checking sir

okay

but sir in the 2nd 2 the - charge on para why don't go for further resonance

Simun, negative charge para pr jada stable hoga

yha pr extended resonance he

or para position pr negative charge ka repulsion minimum hota he so most stable so para product bnega

extended resonance means

sir e density ortho or pare do no me jyada hota he na

yes

tho fir ye after resonance para position bala negative charge kun nahi gaya ortho pe

show nhi kiya, kyoki less stable hoga, ortho pr negative charge jada repulsion krega

jb 1 se jada double bonds conjunction me hote he to ise extended conjunction bol dete he

sir ortho pe kyun nahi

less stable ortho pe kyun ho ga sir udhar bhi e density hota he na

negative charge oxygen k lone pair se repulsion krega na

sir but ye c tak ane se pahele B mein negative charge pe tho ata he na

yes, it's correct 👍

mechanism me direct de diya

but sir iskbad bhi ek steep hoga na jisme ortho pe negative ho ga para in point of view of Stability of negative charge the reagent attack on the negative on para

is this statement correct sir

yes, it show 5 RS pr yha only para product bnega so sari resonating structure show ni krke, only para wali show kr di

so only para is stable here

yes

tq sir 😊🙏🙏

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Simun here para products predominates and when there is any substituent present in para position then it gives ortho product..... see the intermediate

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sry sir

why only para

here simun stabilised carbanion is formed

and also.it is experimentally evidenced that para is major product

ok sir tqsir

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