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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Shweta Thakur posted an Question
November 07, 2020 • 01:18 am
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30 points
30 points
- IIT JAM
- Chemistry (CY)
Why second is not possible. ??? eraction. step 3. the carbocation formed is step 2 can either undergo nucleophilic attack by the
L es energ ch is supplied by the energy ation by ion-dipole interaction. Step 3. The carbocation formed is step 2 can either undergo nucleophilic attack by the bisulphate 10n UIl U Cart carboca (HSOg) or may eliminate a proton. Since HSOis a very weak nucleophile, therefore, nucleophilic substitunon reaction does not occur. Instead elimination of a proton occurs to form ethylene Fast LCH,CH, CH-CH, +H (Elimination) CH CH2 tOSO,H CH,CH-OSO H (Nucleophilic substitution) The whole process is reversible. In order to shift the equilibrium towards right, strong acids and high temperatures are used when the resulting alkene being more volatile than the starting alcohol escapes from the reaction mixture.
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Priyanshu kumar Best Answer
It is mentioned there shweta Hso4- is a weak nucleophile so nucleophilic substitution does not occur
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why it is weak
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perfect nucleophile is like a tip of a spear, all negative charge is located on one atom and no any steric hindrance around it. In these molecules the negative charge is equally delocalized on 4 and, respectively 3 oxygen atoms making it just 25% and ~33% of the perfect nucleophile
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delocalised negative charge hai..so perfect nucleophile nhi hai ye
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ok
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sir
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Suman Kumar
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HSO4 - is a very poor nucleophile so it can't attack the carbocation instead it will abstract the proton
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Dinesh khalmaniya 1
HSO4- is weak nucleophile so nucleophilic substitution don't occur but here elimination can take place. nucleophilic substitution depends on concentration of reactant as well as nucleophile. so strong nucleophile prefer SN reaction