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Shweta Thakur posted an Question

November 27, 2020 • 02:09 am

30 points

IIT JAM
Chemistry (CY)

Why the + 2 oxidation state is more stable for transition elements

why the + 2 Oxidation state is more stable for transition elements

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Dinesh khalmaniya 1 Best Answer

This is due to their electron configuration! This is due to their electron configuration! ... Because only two electrons can exist in an S orbital, and removing the electrons from the sub shell below it requires immense amounts of energy, this limits them to a +2 charge most of the time.
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pls tell me one thing that what is the realation between oxidizing agent reducing agent with acid and base
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A reducing agent (also called a reductant or reducer) is an element or compound that loses (or "donates") an electron to an electron recipient (oxidizing agent) in a redox chemical reaction. A reducing agent is thus oxidized when it loses electrons in the redox reaction.
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sir strong oxidizing agent mean that it's a strong acid
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sir means cr2o7 is strong acid than moo3 and wo3
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yha Cr ki oxidation state +7 he mean jada strongly electrons accept krega mean strong oxidizing agent.
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oxidizing agent mean jo dusro ka oxidation krte he pr khud ka reduction hota he
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yha Cr+7 ka reduction hoga mean electron acceptor he so it is strong oxidizing agent
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sir ni samgh aa rha
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sir cr2o7 Jada acidic hai wo3 and moo3
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Cr+7 jada acidic hoga na
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most oxidinzin agent Jada acid kyun hote hai
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because oxidising agent electrons dete he or jo electron dete he unhe acid bolte he
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main bhi yhi SB Soch ri hun fr confuse kyin ho ri hun
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got it?
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Priyanshu kumar

It is due to the difference in their second and third ionisation enthalpies. Due to the large difference in the second and third ionisation enthalpies arising from the disturbal of the stable half filled electronic configuration, +2 oxidation state is more favourable.
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And the relative stability of +2 oxidation state increases on moving from Sc to Zn. This is because on moving from left to right, it becomes more and more difficult to remove the third electron from the d-orbital because of the increasing nuclear charge.
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sir
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