Akhilesh posted an Question
March 12, 2022 • 02:27 am 30 points
  • IIT JAM
  • Physics (PH)

You have a flask of a certain liquid gas at a temperature of -189\\u00b0c. you then heat the gas until its temperature is doubled. find the new temperature in \\u00b0c.

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    Ravi bhushan Best Answer

    Temperature of liquid gas in Kelvin = -189 + 273.15 = 84.15 K. Final temperature = 2 × 84.15 = 168.30 K in °c = 168.30 - 273.15 = - 104.85°c

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